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NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests

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NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests
NumericalReasoningTest22-Solutions_2025春招题库汇总_八大题库-1_04八大汇总_信永中和_专业题综合知识-参考_英文题_NumericalReasoningTests

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Numerical Comprehension Test 6 Solutions Booklet Instructions This numerical reasoning test comprises 18 questions, and you will have 18 minutes in which to correctly answer as many as you can. Calculators are permitted for this test, and it is recommended you have some rough paper to work on. You will have to work quickly and accurately to perform well in this test. If you don't know the answer to a question, leave it and come back to it if you have time. Each question will have five possible answers, one of which is correct. If the exact correct answer is not provided, select the closest possible answer. You may click Back and Next during the test to review or skip questions. You can submit your test at any time. If the time limit is up before you click submit the test will automatically be submitted with the answers you have selected. It is recommended to keep working until the time limit is up. Try to find a time and place where you will not be interrupted during the test. The test will begin on the next page. AssessmentDay Practice Aptitude TestsQ1 A store bought garden pond has a 1,200 litre capacity. A garden hose is able to discharge 0.6 litres of water per second. How long in minutes would it take to fill the garden pond to 80% capacity using this garden hose? (A) 24.6 minutes (B) 25.1 minutes (C) 26.7 minutes (D) 27.8 minutes (E) 29.3 minutes Step 1 – Calculate 80% of the ponds capacity by multiplying the total capacity of the pond by 80% (0.80). 1,200 x 0.8 = 960 litres Step 2 – Calculate the water discharge rate of the hose in minutes by multiplying the discharge rate in seconds (0.6) by 60. 0.6 x 60 = 36 litres per minute Step 3 – Calculate the time required to fill the pond to 80% capacity by dividing the necessary capacity (960) by the discharge rate in minutes (36). 960 / 36 = 26.6667 = 26.7 minutes Thus the correct answer is (C) 26.7 minutes For personal use only. Unauthorised copying or Page 2 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q2 An online advertisement was viewed by 100,019 people in one day. Of these people, 2.3% clicked on the advertisement. Of those that clicked on the advertisement, 5% made a purchase. The average purchase on the website is £35.40, how much revenue was generated from sales on this day? (A) £3,624 (B) £3,758 (C) £3,824 (D) £3,944 (E) £4,071 Step 1 – Calculate the number of people that clicked on the advertisement by identifying 2.3% of 100,019. 0.023 x 100,019 = 2,300.437 = 2,300 Step 2 – Calculate the number of people that made purchases by identifying 5% of 2,300. 2,300 x 0.05 = 115 Step 3 – Calculate the revenue generated by multiplying the number of sales (115) by the average purchase amount (£35.40). 115 x £35.40 = £4,071 Thus the correct answer is (E) £4,071 For personal use only. Unauthorised copying or Page 3 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q3 Alpacas need to eat 1.5 % of their bodyweight in food per day, and the average weight of an alpaca is 150 lbs. If alpacas eat hay, and a 20 lb. bale of hay can be purchased for £2.99, how much would it cost to feed an average alpaca for a year (52 weeks)? (A) £114.75 (B) £122.59 (C) £138.24 (D) £142.54 (E) £163.14 Step 1 – Calculate the daily food requirements of an average alpaca for a day by identifying 1.5% of the average alpacas bodyweight (150). Then multiply this by 7 in order to work out the weekly total. 150 x 0.015 = 2.25 lbs 2.25 x 7 = 15.75 lbs Step 2 – Calculate the yearly food requirements of an average alpaca by multiplying the weekly food intake by 52. 15.75 x 52 – 819 lbs Step 3 – Calculate the cost of the alpacas food requirements by dividing the annual food requirement by 20 (20 lbs, and rounding up to the nearest whole bale) and multiplying that figure by the price per bale (2.99). 819 / 20 = 40.95 = 41 bales of hay 41 x 2.99 = £122.59 Thus the correct answer is (B) £122.59 For personal use only. Unauthorised copying or Page 4 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q4 After undergoing a quality standards training program, John was able to produce 35 widgets per hour, compared to 29 widgets per hour prior to the training program. If John works 40 hours per week, how many more widgets per week does John produce since the training program? (A) 240 widgets (B) 250 widgets (C) 260 widgets (D) 270 widgets (E) 280 widgets Step 1 – Calculate the number of widgets John produces per week following the training program by multiplying the hourly number of widgets (35) by the number of hours worked per week (40). 35 x 40 – 1,400 widgets Step 2 – Calculate the number of widgets John produced per week prior to the training program by multiplying the hourly number of widgets (29) by the number of hours worked per week (40). 29 x 40 = 1,160 widgets Step 3 – Calculate the increase in number of widgets produced per week by subtracting the old weekly production (1160) from the new one (1,400). 1,400 – 1,160 = 240 widgets Thus the correct answer is (A) 240 widgets For personal use only. Unauthorised copying or Page 5 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q5 Ralph sells his product for £9.99 to customers. He purchases his product at the wholesale price of £39.50 for a pack of ten. How much profit would Ralph make through the retail sale of 125 units of his product? (A) £720.75 (B) £725.25 (C) £730.75 (D) £735.25 (E) £740.75 Step 1 – Calculate the revenue generated through the sale of 125 units of Ralphs product by multiplying the number of units (125) by the unit cost (£9.99). 125 x 9.99 – £1,248.75 Step 2 – Calculate the cost of purchasing the required units by dividing the number of required units (125) by the size of the pack (10), then multiplying by the cost per pack (remember to round up to the nearest whole pack). 125 / 10 = 12.5 = 13 packs 13 x 39.5 = £513.50 Step 3 – Calculate the profit by subtracting the purchasing costs from the revenue to identify the profit. £1,248.75 – £513.50 = £735.25 Thus the correct answer is (D) £735.25 For personal use only. Unauthorised copying or Page 6 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q6 A country sees 21,634 males and 22,028 females born in one year. If the country has a population of 32.4 million people, what percentage of the population are female? (A) 50.2% (B) 50.3% (C) 50.4% (D) 50.5% (E) Cannot say Step 1 – We are only given the number of births for each gender for one year. We cannot generalise from that one year as to what the gender ratio would be in the general population. Thus the correct answer is (E) Cannot say For personal use only. Unauthorised copying or Page 7 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q7 A van is able to transport 0.8 metric tons of confidential documents when fully laden. A corporate headquarters needs to transport 29 metric tons of confidential documents. If the van can make two journeys per day, how many days will it take to transport all of the documents? (A) 17 days (B) 18 days (C) 19 days (D) 20 days (E) 21 days Step 1 – Calculate the weight which can be moved per day by multiplying the maximum weight carried by the van (0.8) by two (two journeys per day). 0.8 x 2 = 1.6 metric tons. Step 2 – Calculate the number of days required to transport the documents by dividing the total weight of the documents (29) by the amount that can be transported per day (1.6).(remember to round up to the nearest day) 29 / 1.6 = 18.125 = 19 days Thus the correct answer is (C) 19 days For personal use only. Unauthorised copying or Page 8 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q8 One Japanese Yen is valued at 0.0066 British pounds. One British pound is valued at 1.57 US dollars. What is the value of 1,250,000 Japanese yen in US dollars? (A) £9,954.50 (B) £10,956.50 (C) £11,785.50 (D) £12,952.50 (E) £13,878.50 Step 1 – Calculate the value of the Japanese Yen in pounds by multiplying the number of Yen (1,250,000) by the 0.0066. 1,250,000 x 0.0066 = £8,250 Step 2 – Calculate the number of US dollar that can be exchanged for British pounds by multiplying the number of Pounds (£8,250) by the number of US dollars per pound (1.57). £8,250 x 1.57 =£12,952.50 Thus the correct answer is (D) £12,952.50 For personal use only. Unauthorised copying or Page 9 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q9 50kg of sugar juice can be extracted from 100kg of sugarcane, which is used to produce sugar. Of this sugar juice, 22% is pure sugar and can be extracted. Using 10 metric tons of sugarcane, how much sugar can be produced? (1 metric ton = 1,000kg) (A) 900kg (B) 1,000kg (C) 1,100kg (D) 1,200kg (E) 1,300kg Step 1 – Calculate the amount of sugar juice that can be extracted from 10 metric tons (10,000kg) of sugarcane by dividing the amount of sugarcane by 2. 10,000kg / 2 = 5,000kg Step 2 – Calculate the amount of sugar that can be extracted from this juice by identifying 22%. 5,000 x 0.22 = 1,100kg Thus the correct answer is (C) 1,100kg For personal use only. Unauthorised copying or Page 10 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q10 A commodities trader purchased 2.5 metric tons of Zinc at the market price of $1,823.50 per metric ton. Three weeks later, the price per ton of zinc rose to $2,018.50. If the trader charges a 15% commission fee on all profits generated, how much commission will the trader have earned? (A) $67.52 (B) $70.54 (C) $73.13 (D) $76.25 (E) $79.51 Step 1 – Calculate the cost of 2.5 tons of zinc by multiplying the price per ton ($1,823.50) by the number of tons purchased (2.5). 2.5 x $1,823.50 = $4,558.75 Step 2 – Calculate the value of 2.5 tons of zinc three weeks later by multiplying the new price per ton ($2,018.50) by the number of tons (2.5). 2.5 x $2,018.50 = $5,046.25 Step 3 – Subtract the previous value of the zinc ($4,558.75) by the new value of the zinc ($5,046.25) to identify the profit generated from the transaction. $5,046.25 - $4,558.75 =$487.5 Step 4 – Calculate the trader’s commission by identifying 15% of the profit ($487.5). $487.5 x 0.15 = $73.125 = $73.13 Thus the correct answer is (C) $73.13 For personal use only. Unauthorised copying or Page 11 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q11 Two competitors sell product A. At competitor 1, product A is sold for £9.99. At competitor 2, product A is sold for £8.99. If competitor 1 purchases product A for the wholesale price of £4.50 each, and competitor 2 purchases product A for the wholesale price of £4.00, how much extra profit is generated from 150 sales by competitor 1 than competitor 2? (A) £75 (B) £80 (C) £85 (D) £90 (E) £95 Step 1 – Calculate the revenue generated by 150 at competitor 1 and 2 by multiplying their respective sales prices by the number of sales (150). Competitor 1 = 9.99 x 150 =£1,498.50 Competitor 2 = 8.99 x 150 =£1,348.50 Step 2 – Calculate the costs of purchasing product A by multiplying the wholesale price paid for each respective company by the number of sales (150). Competitor 1 = 4.50 x 150 =£675 Competitor 2 = 4.00 x 150 =£600 Step 3 – Calculate the profit generated by subtracting the costs from the revenue for each respective competitor. £1,498.50 - £675 = £823.50 £1,348.50 - £600 = £748.50 Step 4 – Calculate the difference in profit by subtracting the profit generated by competitor 2 from the profit generated by competitor 1. £823.50 - £748.50 = £75 Thus the correct answer is (A) £75 For personal use only. Unauthorised copying or Page 12 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q12 The total population of the people’s republic of China is 1,353,821,000 and the total population of India is 1,210,569,573. The total gross domestic product (GDP) of the people’s republic of China is $13.623 trillion and the total GDP of India is $4.711 trillion. What is the difference between the average GDP per capita (per person) in the people’s republic of China and India? (A) $5,789.78 (B) $5,862.24 (C) $5,965.50 (D) $6,064.85 (E) $6,171.07 Step 1 – Calculate the GDP per capita in China by dividing the GDP by the population of China. $13,623,000,000,000 / 1,353,821,000 = $10,062.63014 = $10,062.63 Step 2 – Calculate the GDP per capita in India by dividing the GDP by the population of India. $4,711,000,000,000 / 1,210,569,573 = $3,891.55659 = $3,891.56 Step 3 – Calculate the difference by subtracting the GDP per capita of India from the GDP per capita of China. $10,062.63 - $3,891.56 = $6,171.07 Thus the correct answer is (E) $6,171.07 For personal use only. Unauthorised copying or Page 13 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q13 A car traveling at 29 miles per hour drives into a tunnel which is 7km long. How long does it take the car to fully pass through the tunnel? (1 mile = 1.609344km) (A) 6 minutes (B) 7 minutes (C) 8 minutes (D) 9 minutes (E) 10 minutes Step 1 – Calculate the length of the tunnel in miles by dividing the length the of the tunnel (7) by the number of kilometres in a mile (1.609344km) 7 / 1.609344 = 4.3496 Step 2 – Calculate the speed of the car in miles per minute by dividing the cars speed in miles per hour (29) by 60. 29 / 60 = 0.48333 miles per minute Step 3 – Calculate the number of minutes required to travel the length of the tunnel by dividing the length of the tunnel (4.3496) by the speed of the car in miles per minute (0.48333). 4.3496 / 0.48333 = 8.999234477 = 9 minutes Thus the correct answer is (D) 9 minutes For personal use only. Unauthorised copying or Page 14 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q14 A numerical reasoning test contains 18 questions, with a time limit of 30 seconds per question. A candidate takes 20 seconds to complete 6 questions, 25 seconds to complete 5 questions and 18 seconds to complete 7 questions, how much time went unused from the overall time limit of the test? (A) 136 seconds (B) 147 seconds (C) 158 seconds (D) 169 seconds (E) 180 seconds Step 1 – Calculate the time spent answering the questions by multiplying the time taken for the respective questions by the number of questions. 20 x 6 = 120 seconds 25 x 5 = 125 seconds 18 x 7 = 126 seconds Total = 120 + 125 + 126 = 371 Step 2 – Calculate the full length of the test by multiplying the time limit per question (30) by the number of questions (18). 30 x 18 = 540 seconds Step 3 – Calculate the time to spare at the end of the test by subtracting the actual time taken (371) by the time limit (540). 540 – 371 = 169 seconds Thus the correct answer is (D) 169 seconds For personal use only. Unauthorised copying or Page 15 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q15 A film was recently released on DVD and during its first week of sales, 2,150 copies are sold. If the DVD is sold for £9.99 each, how much revenue was made on average per day during the first week of sales? (A) £2,954.21 (B) £3,068.36 (C) £3,145.87 (D) £3,245.96 (E) £3,354.35 Step 1 – Calculate the revenue generated by multiplying the number of sales (2,150) by the individual sales price (£9.99). £9.99 x 2,150 = £21,478.50 Step 2 – Calculate the average revenue per day by dividing the total weekly revenue by 7. £21,478.50 / 7 = £3,068.357143 = £3,068.36 Thus the correct answer is (B) £3,068.36 For personal use only. Unauthorised copying or Page 16 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q16 A cola drink contains a secret ingredient. Every litre of cola contains 32 grams of this secret ingredient. If the cola is sold wholesale by the barrel, and each barrel contains 40 gallons of cola, how much of the secret ingredient is present in the barrel? (1 gallon = 4.54609 litres) (A) 5,475 grams (B) 5,585 grams (C) 5,657 grams (D) 5,759 grams (E) 5,819 grams Step 1 – Calculate the number of litres of cola in each barrel by multiplying the volume of cola (40) by the number of litres per gallon (4.54609). 40 x 4.54609 = 181.8436 Step 2 – Calculate the amount of secret ingredient per barrel by multiplying the number of litres (181.8436) by the number of grams of secret ingredient per litre (32). 181.8436 x 32 = 5,818.9952 = 5,819 grams Thus the correct answer is (E) 5,819 grams For personal use only. Unauthorised copying or Page 17 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q17 An art broker sells paintings from leading artists for a commission of 10%. Similarly, when auctioning paintings, the broker earns an additional £150 per item through auction fees. If the broker sells 8 paintings not at auction for £8,000 a piece, and sells 4 paintings at auction for a total of £32,000, how much does the broker earn in total? (A) £10,200 (B) £11,400 (C) £12,600 (D) £13,800 (E) £15,000 Step 1 – Calculate the total commission earned on the non-auctioned items by multiplying the number of items (8) by their sale price (8,000), and then identifying 10%. 8 x £8,000 = £64,000 £64,000 * 0.1 = £6,400 Step 2 – Calculate the total commission earned from the auctioned items by identifying 10% of the auctioned total (£32,000), plus the additional auction fee (150). £32,000 * 0.1 = £3,200 £150 x 4 = £600 £3,200 + £600 = £3,800 Step 3 – Calculate the total amount earned by the broker by combining the total revenue of the auctioned and non-auctioned items. £6,400 + £3,800 = £10,200 Thus the correct answer is (A) £10,200 For personal use only. Unauthorised copying or Page 18 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.Q18 A bamboo shoot grows at a rate of 95cm per day under optimum circumstances. If a bamboo field contains 1,500 bamboo shoots, how much additional length would be gained in total over a week under optimum circumstances? (A) 987,500 (B) 997,500 (C) 107,500 (D) 117,500 (E) 127,500 Step 1 – Calculate the daily length gained in the field by multiplying the daily length increase per plant (95) by the number of plants (1,500). 1,500 x 95cm = 142,500 cm Step 2 – Calculate the weekly length gained in the field by multiplying the total daily length increase by 7. 142,500 cm x 7 = 997,500 Thus the correct answer is (B) 997,500 -- End of Test -- For personal use only. Unauthorised copying or Page 19 AssessmentDay distribution in printed, electronic, or any other form in whole or in part, is prohibited without Document last updated 15-10-2013 www.assessmentday.co.uk prior written permission from AssessmentDay.