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高二数学_2024-2025高二(7-7月题库)_2024年07月试卷_0712四川省绵阳市2023-2024学年高二下学期期末考试_四川省绵阳市2023-2024学年高二下学期期末教学质量测试数学试题

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高二数学_2024-2025高二(7-7月题库)_2024年07月试卷_0712四川省绵阳市2023-2024学年高二下学期期末考试_四川省绵阳市2023-2024学年高二下学期期末教学质量测试数学试题
高二数学_2024-2025高二(7-7月题库)_2024年07月试卷_0712四川省绵阳市2023-2024学年高二下学期期末考试_四川省绵阳市2023-2024学年高二下学期期末教学质量测试数学试题
高二数学_2024-2025高二(7-7月题库)_2024年07月试卷_0712四川省绵阳市2023-2024学年高二下学期期末考试_四川省绵阳市2023-2024学年高二下学期期末教学质量测试数学试题
高二数学_2024-2025高二(7-7月题库)_2024年07月试卷_0712四川省绵阳市2023-2024学年高二下学期期末考试_四川省绵阳市2023-2024学年高二下学期期末教学质量测试数学试题
高二数学_2024-2025高二(7-7月题库)_2024年07月试卷_0712四川省绵阳市2023-2024学年高二下学期期末考试_四川省绵阳市2023-2024学年高二下学期期末教学质量测试数学试题
高二数学_2024-2025高二(7-7月题库)_2024年07月试卷_0712四川省绵阳市2023-2024学年高二下学期期末考试_四川省绵阳市2023-2024学年高二下学期期末教学质量测试数学试题
高二数学_2024-2025高二(7-7月题库)_2024年07月试卷_0712四川省绵阳市2023-2024学年高二下学期期末考试_四川省绵阳市2023-2024学年高二下学期期末教学质量测试数学试题

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高中 2022 级第二学年末教学质量测试 数学参考答案及评分标准 一、选择题:本题共8小题,每小题5分,共40分. 1.A 2.D 3.B 4.C 5.D 6.D 7.B 8.C 二、选择题:本大题共3小题,每小题6分,共18分。在每小题给出的四个选项中,有 多项符合题目要求。全部选对的得6分,选对但不全的得部分分,有选错的得0分. 9.ABD 10.CD 11.ABC 三、填空题:本题共3个小题,每小题5分,共15分. 12. ; 13. ; 14.4. 四、解答题:本题共5小题,第15题13分,第16、17小题15分,第18、19小题17 分, 共77分.解答应写出文字说明、证明过程或演算步骤. 15.解:(1)高二年级至少2名同学入选校队包括以下情况: 高二年级仅2名同学入选校队有 种;········································2分 高二年级仅3名同学入选校队有 种;·········································3分 高二年级4名同学入选校队有 种;·············································4分 高二年级至少2名同学入选校队共有18+12+1=31种选法.··························6分 (2)由题意可知,随机变量X的取值为0,1,2,3,································7分 校队由0个女生4个男生组成时, ,···························8分 校队由1个女生3个男生组成时, , ··························9分 校队由2个女生2个男生组成时, ,·························10分 校队由3个女生1个男生组成时, , ························11分 所以,随机变量X的分布列为 X 0 1 2 3 数学试题卷 第1页(共6页) 学科网(北京)股份有限公司P ···································································································12分 随机变量X的均值为: .··························13分 16.解:(1) ,令 ,则 , ,·············2分 ①当a=0时, ,所以 为增函数,故 无极值点;·······3分 ②当a>0时,当x变化时, 及 变化如下表: x −a + 0 − 0 + 递增 极大值 递减 极小值 递增 由此表可知 的极值小点为 ,其极大值点−a;···································5分 ③当a<0时,当x变化时, 及 变化如下表: x −a + 0 − 0 + 极小 递增 极大值 递减 递增 值 由此表可知 的极值小点为−a,其极大值点 .···································7分 综上所述,当a=0时, 无极值点;当a>0时, 的极值小点为 ,极大值点 −a;当a<0时, 的极值小点为−a,其极大值点 .·····························8分 (2)方法一:假设存在实数a,使得在区间[0,1]的最小值为0,且最大值为1, 则 [0,1], ;································································9分 由已知可得, ,则 ,·············································10分 数学试题卷 第2页(共6页) 学科网(北京)股份有限公司由(1)②可知, 在区间[0, ]上单调递减,在[ ,1]上单调递增, ∴ ,···········································11分 ······················································································13分 ∴ , , ,则 成立,解得: , ∵ ∵ , ∴当 时, ,即 的最大值为 ,···14分 所述,满足题意的 .···························································15分 综上 方法二:假设存在实数a,使得在区间[0,1]的最小值为0,且最大值为1, 则 [0,1], ;·································································9分 由已知可得, ,则 ,···········································10分 由(1)②可知, 在区间[0, ]上单调递减,在[ ,1]上单调递增, ∴ ,···········································11分 ∴ ······················································································13分 , ∵ , , 令 ,则 的零点为 ,且 在 上单调 递增, 数学试题卷 第3页(共6页) 学科网(北京)股份有限公司∵ ,则 , ∴当 时,则 成立,则 ,即 的最大值为 ,符合题意,·········································································14分 综上所述, .··········································································15分 17.解:(1)由 ,可知当 时, ;··················1分 当 时, ,即 ,其中 也满足; 综上, .·····························································3分 又数列 满足 ,且 , 当 时,可得: , ········································································································5分 当 时, 适合上式, 所以数列 的通项公式为 .·······························7分 (2)由于 ,·····················································8分 则 ,·············10分 即 , ·································12分 两式相减得: , ,·······················································14分 所以 .············································15分 数学试题卷 第4页(共6页) 学科网(北京)股份有限公司18.解析:(1) ,则 ,····························1分 ∴切线斜率为: ,又 ,··················································2分 ∴所求切线方程为 ;·····························································4分 (2)方法一:函数 的定义域是 , ∴ ,······································································5分 ①若a≤0,则 , 在 上单调递增, , , ∵ , , ,则 , 则 仅有一个零点,且零点位于(1, ];···········································7分 ②当 , 在 单调递减, 在 单调递增; 因为 的最小值为: , 若a>1时, ,此时 无零点;··········································8分 若a=1时, ,此时 仅有一个零点;·································9分 若01.···············································································10分 方法二:令 ,则 ,····················································5分 设 ,则 ,·······················································7分 ∴ 在(0,1)上单调递增,在(1,+∞)上单调递减, ∴ 的最大值为 ,且x>e, ,·········································9分 ∴要使 在定义域上无零点,则a>1.···············································10分 (3)令 (x≥1), 则 ························································11分 数学试题卷 第5页(共6页) 学科网(北京)股份有限公司①当a<1时,x−a>0,∴ 时, , 在 上单调递减, 此时, ,不符合题意;·············································13分 ②当a=1时, ∴ 时, , 在 上单调递减, ∴ ,即x=1时, ,符合题意;····································15分 ③当a>1时, ∴ 时, , 在(1,a)上单调递增; 时, , 在 上单调递减, ∴ , ,符合题意; 综上所述,a≥1.··············································································17分 19.解:设事件 表示:第 天中午去A餐厅用餐, 事件 :第i天中午去B餐厅用餐,其中 , ,…….···························1分 (1)小王第2天中午去A餐厅用餐的概率为: ∴ ;····················4分 (2)设 ,依题可知, , , ∵如果小王第1天中午去A餐厅,那么第2天中午去A餐厅的概率为0.8, 即 ,而 , ∴ ,·······························································5分 ∵如果第1天中午去B餐厅,那么第2天中午去A餐厅的概率为0.4, ∴ .·································································6分 由全概率公式可知 , 即 ,··········································································7分 ∴ ,而 ,························································8分 ∴数列 是以 为首项,以 为公比的等比数列,······························9分 ∴ ,即 ;·····················································10分 (3)设王某第i天去B餐厅的次数为Xi ,则Xi 的所有可能取值为0,1,·····11分 数学试题卷 第6页(共6页) 学科网(北京)股份有限公司当Xi=0时表示王某第i天没去B餐厅,当Xi=1时表示王某第i天去B餐厅, ∵ , , ∴ ,··················································13分 ∵ , , ,2,……,······································15分 ∴当 n∈ N*时, ,·······················16分 故 .··································································17分 数学试题卷 第7页(共6页) 学科网(北京)股份有限公司