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更多上海四校八大冲刺资料、25 一模最新真题及答案解析、自招全科真题等，加清浅老师微信领取
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B
A
D
A
C
D
↓
3更多上海四校八大冲刺资料、25 一模最新真题及答案解析、自招全科真题等，加清浅老师微信领取
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2-
k-2
2
5
I
Z
42
.
300+100
E
9-2
3E 3
.
T
E 0 Y F
4 + H
#
j-,)
96 &
=
,
LBFG 21
=
= 54
I
By CG=
55
M I 45 W 68380 #
& ABGY OFDI Es S
I E
30 K
↳ & bee 450 40
2 E #
H5
-DH F
=
=更多上海四校八大冲刺资料、25 一模最新真题及答案解析、自招全科真题等，加清浅老师微信领取
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E
+
#5
=
=
B
=
F-# L
↓
ni
2
G
11) L
=
i GD = 2 AG = 4
,
in AF = 3更多上海四校八大冲刺资料、25 一模最新真题及答案解析、自招全科真题等，加清浅老师微信领取
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-
⑧
= ⑧ ↑
= 6
11:
De Ac = CB= AD CBDC= LABC = 90:
12) :CB= AD ↓, = E
= RtAADBIP Sin A
:
=
LA ! BD= 35 - 3
↓ =LC ,
=F
RtAABC: sinA UBCDDABC
= 1 :
= AHAD-DH= 8 tanz =
DH =3 6m ,
. .
k
*
1,6 4
H
! -18
22
↑
121 LAPF= 45 APLOG
.
↓ AF= PA = 16 . 4 m
GEFTLACBT
316
FT= AF sin2 = m
.
13 63 3
.
FM
,更多上海四校八大冲刺资料、25 一模最新真题及答案解析、自招全科真题等，加清浅老师微信领取
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&
I
· 1/ 11 * C
BC P h
"AF FC 12) : ETA
11) =
LACF E
is LFAC= i BE = CE = BC
.
LACB LADC LACB
LADC = =
ABC
CDA ↓ DALD v 0
↓ DACEnO
=
i
ACE
AD AB
ACE HE :
i CD ·
.
LBCA
LACE
LEAC LB =
↓ = ,
-LACE nOBCA
E
↓
Ach
CE.BC =
i
AB
AD
i EBC BC = :
-
,
AB
BCE ZAD
: .
1更多上海四校八大冲刺资料、25 一模最新真题及答案解析、自招全科真题等，加清浅老师微信领取
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U
j...
(1) 3= 16 + 4b + C & = =4-
(x
= 2
= - REIJING Y (1 +12 + m P(t m)
= - , ,
12 R10 . 3) <(2 , -1) IX-t2
I
O) =
PEXTEL PIt
& ,
, -5
=Ets Xi=
47 +3 * X .
& (
=
,-
1 + 10bt + + 530 +> - it 4+ B
,
2 > #f +
,
- 514 t =
4+5
,
Y X X=2 & PIt t = 4t+ 3)
,
(0 , 3) B . D C. EDI 1 =(x - +P + +2 4t+3
M1 P E =
... --
2 - St + 7) tanLao =
> X = D(2 ,
O
(12-1) cm =
t = 4t+ 4
t 2 4++4
DM= -
DM
=, CM =
ELDPC
CCPM =
CDPM
- =
=
tanLepm
= =
t 4 ++ 4 t t
in
- =
t 2
-
-4)
P(
=
,更多上海四校八大冲刺资料、25 一模最新真题及答案解析、自招全科真题等，加清浅老师微信领取
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- -
↓ 3k ↓
X S
O
F 8
4k
M
N
I
2
A
LA=LB
LBDF
(1) LADE= , X
39
UBDF z
i DADEn
D ⑧
i O 3a 1 E
#
39 - I
2a
DE 3
is cotLEPF = EFT B X X O 2
EEFEFN llAB Fl
ZEYEEM 11 AB
12) . : LCEF = LAED
X
EM 11 FN LA LB=
i < C= CADE = o
,
LCFE= =
M
↳ EF11AB 1 CF= 1 . BF = 2 ,
iREF=29
,
N AB= 6a
,
BD =
3a
D + 0
DEA
CEF TO
O =
EDELBEAC 29 Ab
= I - : a
2
A
20
LC= LA
*F
X
MADENORDE) za
2 L= LA= LB=
60:
Do
E
O ! AB=Bl= 3
&
3-29 - I
X
B I oX
C
3-a A
F
F
, =
AED
· CEF no
iCF a
M) AD=2 a
=
,
#,
↓
YOBFD
- CEF , CF
2 = E
a 5a+3= 0
B
!,
AD =2a= 5-
