文档内容
高中 2022 级第二次诊断性考试
数学参考答案及评分标准
一、选择题:本题共8小题,每小题5分,共40分.
1.D 2.A 3.C 4.B 5.D 6.B 7.A 8.C
二、选择题:本大题共3小题,每小题6分,共18分.在每小题给出的四个选项中,有多项符合题目
要求.全部选对的得6分,选对但不全的得部分分,有选错的得0分.
9.BCD 10.BC 11.ABD
三、填空题:本题共3个小题,每小题5分,共15分.
12.3; 13. ; 14.
四、解答题:本题共5小题,第15题13分,第16、17小题15分,第18、19小题17分,共77分.解
答应写出文字说明、证明过程或演算步骤.
5.解:(1)∵ ,
1
由正弦定理得:
,····························································2分
又 则 ,
,
∴ ,····················································································4分
∴
,又B是三角形内角,··········································································5分
∴
;········································································································6分
2)∵ ,且 ,
(
∴
,···································································································8分
∴
,·························································································9分
∴
,·························································································11分
∴
.····································································································13分
16.解:(1)a=0时, , ,且 ,······························2分
∴ ,·································································································4分
故切线方程为:y−(e+1)=e(x−1),即ex−y+1=0;·························································6分
(2)∵ , ,·········································································7分
由10),易知 , ,
设平面ACE的法向量为:n=(x,y,z),
1
∴ ,不妨令 ,则平面ACE的一个法向量为:n=(0,−n,m),
1
又平面ACD的一个法向量为n=(0,0,1),·································································7分
2
∴cos= ,······························································8分
1 2
∵ ,则 ,
解得:n= ,则点E到平面ACD的距离为 ,
由E为PD的中点,则点P到平面ACD的距离为 ,·················································9分
在△ACD中,AC=AD=2,满足 ,
∴AD⊥AC,则△ACD的面积为2,···········································································10分
∴三棱锥P-ACD的体积 ;··························································11分
(3)由PC//EG,则直线PC与平面ACE所成角即为直线EG与平面ACE所成角,设为θ,
由 ,则 ,·································································12分
·····················13分
∴
······························14分
∴
(当且仅当m=1时,等号成立)·······················16分
数学参考答案 第5页(共6页)即 的最大值为 ,
∴直线PC与平面ACE所成角正弦值的最大值为 .················································17分
19.解:(1)由已知得, ,即 ,······················································1分
又离心率为 ,则 ,
∵ ,所以 ,即 ,·····························································2分
∴ , ,·································································································3分
∴椭圆Г的标准方程为: ;······································································4分
(2)设点M(x,y),则点M满足: ,则 ,
0 0
由已知可得F(0, ),H(0, ),设直线MF与MH的斜率分别为 , ,
∴ , ,···············································································5分
直线MF与MH的斜率之积满足: .······················6分
(i)∵D(2, ),G(2,0),则 , ,
直线PF的方程为: ,令 ,则 ,
∴ ,·····································································································7分
直线HQ的方程为: ,令 ,可得Q(2, ),
∴ ,
∴ ,················································································8分
且 ,·························································9分
∴ ;···················································································10分
(ii) 存在 ,使得|TK|定值 ,理由如下:···················································11分
设点 , , ,
①当过椭圆上点 的直线l斜率存在时,设直线l方程为: ,
数学参考答案 第6页(共6页)带入椭圆Г的方程: ,
化简并整理得: ,
∵直线l与椭圆仅有一个公共点,
∴ ,
化简得: ,····················································································12分
∴ ,代入 ,得 ,
∴ ,
从而直线l的方程为: ,即 ,·············································13分
②当过 的直线l斜率不存在且与椭圆Г仅有一个公共点时,直线l的方程为:
满足上式.
同理:当过椭圆上点 的直线: 与椭圆Г仅有一个公共点,
这两条直线都过点S,所以有 , ,
∴直线IJ的方程为 .···········································································14分
由(i)则直线PF的方程为: ,令 ,则R( , ),
又Q(2, ),
∴RQ的中点S( , ),即 , .
∴直线IJ的方程表示为: ,
即 ,·······································································15分
令 ,解得: ,·······························································16分
∴直线IJ恒过定点N( ),又∵OT⊥IJ,
∴点T在以ON为直径的圆上,即K( ),|TK|定值 .·······································17分
数学参考答案 第7页(共6页)