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上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案

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上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案
上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案
上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案
上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案
上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案
上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案
上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案
上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案
上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案
上海市嘉定区2020届九年级上学期期末(一模)数学答案(word版)_0122026上海中考一模二模真题试卷_2025-2012年_2.上海中考数学一模二模(12-24)_一模_2020年上海市中考数学一模答案

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2020 年上海市嘉定区中考数学一模试卷 参考答案 2020.1 一、选择题(本大题共6题,每题4分,满分24分) 1.D;2.A;3. D;4.A;5.B;6.C. 二、填空题:(本大题共12题,每题4分,满分48分) 7. ;8. ;9. ;10. ;11. ;12. ;13. ;14. ;15.75;16. (不 要求写出函数的定义域);17. ;18. . 三、解答题(本大题共7题,满分58分) 19.(本题满分10分) 解: = ·················································································8分 = .··················································································1+1分 20.(本小题满分10分,第(1)小题6分,第(2)小题4分) 证明:在Rt AOH中, ∵ △ , , , ∴ (m).··································································2分 ∴ (m) ·····························································2分 在Rt BOH中, ∵ △ , , , ∴ ·····································································2分 A O (2)过点 向直线 作垂线,垂足为 .··························································1分 M B H 图6-2在Rt ABM中, △ ∵ , , , ∴ ·····································································2分 答: 的正弦值为 ,点 到直线 的距离是1米.·······································1分 21.(本题满分10分) 解:设 , ,·····································································1分 由题意,得 , ··································································2分 ∵ ,∴ = .·············································································1分 ∴ ,即 .·········································································2分 ∵ 、 、 、 都是⊙O的半径,∴ .····························1分 ∵ , ∴△AOB≌△COD.·························································································2分 ∴ .··································································································1分 22.(本题满分10分) 解:过点 作直线 的垂线,垂足为 (如图7所示)········································1分 由题意,得 , .··························································1分 ∴ .···································································1分 又∵ ,∴ .·····································1分 ∴ .····························································································1分 ∵ ,∴ (海里)··························································1分在Rt△ACD中, (海里)···························2分 由题意知:以海岛A为圆心,半径长为10海里范围内有暗礁.这里, , 所以,如果货轮继续向东航行,没有触礁的危险. ·············································2分 A D E D B C 图7 图8 23.(本题满分12分,第(1)小题4分,第(2)小题8分) 证明:(1)∵ ∥ ,∴ .·······················································1分 又∵ ,∴△BDE∽△CBE. ·························································1分 ∴ .························································································1分 ∴ .··················································································1分 (2)∵ ∥ ,∴ .又 ,∴ .·····················1分 又∵ ,∴△ADE∽△ABE. ····················································1分 ∴ .·······················································································1分 ∵ ∥ ,∴ ,即 .···············································1分 ∴ .·······················································································1分 ∵ 平分 ,∴ ,又∵ ,∴ .·······1分 ∴ .··························································································1分 ∴ .·······················································································1分 24.(本题满分12分,每小题4分)解:(1)图像基本正确(开口方向、对称轴、顶点、大致光滑)··························2分 将图9中的抛物线 向下平移2个单位长,可得抛物线 ················2分 备注:如果使用“列表、描点、连线”的方式叙述,需要呈现列表使用的表格. (2)由题意,得点 的“关联点”为 ·······································1分 由点 在抛物线 上,可得 , ····························1分 又∵ 在抛物线 上,∴ ····································1分 解得 .将 代入 ,得 ··········································1分 (3)点 的“待定关联点”为 ,·············································1分 ∵ 在抛物线 的图像上,∴ .······················1分 ∴ , .又∵ ,∴ .···············································1分 当 时, ,故可得 .··············································1分 25.(本题满分14分,第(1)小题4分,第(2)、(3)小题各5分) 证明:(1)∵ , ,······················1分 ∴ .···················································1分 即 . ∴ .···················································································1分 又∵ ,∴ ∽ .··························································1分 (2)如图10-1,∵ , ,∴ .·················1分 在 中,∵ , ,∴ .····························1分 又∵ ∽ ,∴ .·····················································1分 ∴ ,即 .·································································2分 A A A A P P P P C B C B C B 图10-1 图10-2 C B 图10-3 图10-4(3)∵ , , ,∴ . ∴ .································1分 ∵ ∽ ,∴ ,∴ . ①如图10-2,当 是等腰三角形,且 时, . ···········································································································1分 ②如图10-3,当 是等腰三角形,且 时, , , 易得 ,∴ ·····················································2分 ③如图10-4,当 是等腰三角形,且 时, , , 易得 ,∴ .···················································1分 备注:写出 , 这两个答案之中的一个,即可得到2分;两个 全部写出,得3分.