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2024 学年第一学期丽水五校高中发展共同体期中联考
高一年级物理学科参考答案
命题1：庆元中学 吴 锋 联系电话：13735940160
命题2：松阳一中 王潜龙 联系电话：13757095366
命题3：青田中学 林燕平 联系电话：13567649994
一．选择题
1 2 3 4 5 6 7 8 9 10 11 12 13 14
C D C B A B C C A B D A A A
15 16 17 18
AD AB BC CD
二．非选择题
19.（1）0.05 （2）BD （3）0.475 1.25
20.（1）3.70 （3.68，3.69，3.70，3.71，3.72均给分）（2）B （3）CD （4）丙
21.（1）根据匀变速直线运动公式，可得 ·············································（2分）
解得a=8m/s2·························································································（1分）
（2）根据匀变速直线运动公式，可得v=at ·······················································（2分）
解得 v=24m/s························································································（1分）
（3）由匀变速直线运动平均速度公式可得： ······································（2分）
解得 ··················································································（1分）
22.（1）对结点O受力分析可知 ·················································（2分）
联立解得x=0.32m····························································（1分）
（2）对结点O受力分析可知 ·························································（1分）
对A受力分析可知 ·································································（1分）
联立解得m =5kg·························································································（1分）
A（3） 再次对A受力分析可知 ············································（2分）
解得f=8N，方向沿斜面向下···········································································（2分）
23.（1）由匀变速规律可知 ······················································（3分）
又a=2a 解得a=1.6m/s2，a=0.8m/s2··························································（1分）
1 2 1 2
（2）由匀变速规律可知 解得v=v =0.8m/s，································（1分）
1 m
所以 ························································································（1分）
又感应距离l=v t························································································（1分）
人
解得l=0.75m·······························································································（1分）
（3）搬运物体到感应区后，门先匀加速移动 0.2m，若搬运物体成功，门至少还要匀减速移动
的距离为 ···········································································（1分）
由 可得门做匀减速运动用时 或 （舍去）
则开门用时 ················································································（1分）
可得 所以物体的移动速度 不能超过 ·····························（1分）
