文档内容
2024 届高三定时训练
．．．．
{ 3
y
y
p
}
=
=
A
−
=
1
x
t a n
{ 1
x
, 2 , 3 } B
{
=
1
{
, 3
y
}
| y = 3 x − 3 , x A
{ 3
y
y
}
, 6
=
=
}
e
e
x
−
+
2
x −
2
e −
e
x
x
A B =
{ 0 , 3 , 6 }
x−12 q m − x 0 p q m
m3 m3 m5 m5
f(x) x0 f(x)= x2 +3x+2 x [ 1 , 3 ] f(x)
1 1
2 −2 −
4 4
{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#} A ( 4 , 3 ) tan(+)=2 t a n ( 3 π )
1
2
{ a
n
}
−
1
2
5
2
−
−
=
5
2
n S
n
a 0
n
S
6
= 1 0 S
1 8
= 7 0 S
2 4
=
9 0 1 3 5 1 5 0 1 8 0
sin2x
f(x)=sinx+
2
3
2
3
4
3 5
8
3 5
4
a b
8
( s i n 1 5 − c
c
o s 1 5
d
) 2 =
9
1
2
a −
b
2 e a
=
1
d
−
−
c
1
= 1
1 0
( a − c ) 2 + ( b − d
1
2 )
1
2
sin222.5−cos222.5=−
2
c
(
o
t
s 2
a n 1
8
0
c
o
−
s 3 2
3
)
−
c o
c
s
o
5
s
0
6
2
=
c
−
o s
3
2
5 8 = −
1
2
x y R ， f ( x + y ) = f ( x ) + f ( y ) + 1 x 0
f(x)−1 f(1)=1
f(0)=0
{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}x
f
f
f
( x
( x
(1
)
)
) + f
R
( 2
( 1
)
, 1
+
)
+ f ( 2 0 2 3 ) = 2 0 2 3 2
，y x2 + y2 −xy =3
x + y 2 x + y − 2 3
x2 + y2 6
a f ( x ) = x ( l n x − 2 a x )
x 2 + y 2 4
x
1
x
2
x x
1 2
0
f
( x
a
1
)
1
4
0
x
1
f
+
( x
x
2
2
)
2
−
1
2
{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}f(x)= 1−log (x+2)
2
△ A B C A B C a b c ，
△ A B C
1 2
A =
2 π
3
a = 7 b = 1
3
( 0 , + )
4
f ( x ) f(x)e−x 1
f (
1
2
) = 2 e
A =
x
{ x | a + 1 x 2 a − 1 } B = { x | x 3 x 5 }
f ( l n x ) x + e
a=4 A B
A B a
4
…
2
…
1
5
3
…
6
{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}f ( x ) = x 2 − ( a + 3 ) x + 3 a ， a R
x f ( x ) 0
x[4,+)
f ( x ) = 3
f
s i n
( x
2
)
x + c o s 2 x + 1
f ( x ) − 9 a
△ABC A B C a b c f ( A ) = 2
a=2 3 △ABC
f(x) R
f ( x )
f ( a x 2 − 3 x − 1 ) + f (
x
f
5
( x
−
0
)
a x ) + a
f
x
(
2
x
−
)
(
=
3
x
+
2
a
e
)
x
x + 4 0
xR a
{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}{ a
n
} n S
n
2a S =a 2 +2n
n n n
{ a
n
}
n N * a
n
2 2 − m m
f ( x ) = l n x + m x + 1 g(x)= x(ex −1)
f ( x ) 0 m
x f(x)g(x) m
{#{QQABaYCAggCAAAIAAAhCUwXSCkGQkBCCAKoGBEAIoAABQANABAA=}#}
