专题8.4 直线与圆、圆与圆的位置关系【十大题型】
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ę 1Y2024·ĚěĜĝ·ÃĞZ¡!𝐶:𝑥2 +2𝑥+ 𝑦2−3=0I£𝑙:𝑚𝑥+ 𝑦= 0 ! C "#$%\YğğZ
A
B+
C1
Dp+
Ġt 1-1Y2024·ġĢ·ĞģĤĥZ“𝑘=
12
5 ”\“𝑘𝑥−𝑦+ 1 + 𝑘= 0 !(𝑥−2)2 + (𝑦−3)2 = 4+”"
Y Z
AĦAxħ;Òñ
Bħ;xĦAÒñ
CĦ;Òñ
DĨxĦA|xħ;Òñ
Ġt 1-2Y2024·ĩĪ·ĞģĤĥZī𝑙:𝑥+ (1 + 𝑎)𝑦= 2−𝑎I!𝐶:𝑥2 + 𝑦2−6𝑥+ 4𝑦+ 12 = 0I£Ĭ
ď !"#$%\Y Z
A1
B+
C
Dxî8
Ġt 1-3Y2024·ĭĮyį·°ĞZī𝑙:𝑦= 𝑘𝑥+ 1 !𝐶:(𝑥+ 1)2 + 𝑦2 = 𝑟2(𝑟> 0)I£“∀𝑘∈𝑅I
𝑙 !𝐶{:.”\“𝑟>
2”"Y Z
AĦAxħ;Òñ
Bħ;xĦAÒñ
CĦ;Òñ
DĨxĦA|xħ;Òñ
2 ()*
ę 2Y2024·İı·ĞģĤĥZ𝑙:𝑥+ 𝑦= 1I!𝐶:𝑥2 + 𝑦2−2𝑥−2𝑦−2 = 0.£𝑙IJ!𝐶®ĐÂ"()¬
Y Z
A2
B2 3
C2 7
D 14
Ġt 2-1Y2024·ijĴĵĶķ·°ĞZī𝑎𝑥−𝑦+ 2 = 0 !(𝑥−1)2 + 𝑦2 = 4ò AIB 9.I¡
|𝐴𝐵| = 2 3I£𝑎= YğğZ
A
4
3
B1
C−
3
4
D﹣2
Ġt 2-2Y2024·ĭĮĸĹ·MĞZđ3à´µ%𝑥𝑂𝑦5I𝑙:𝑎𝑥+ 𝑏𝑦= 1-{Ú{M.𝑃Iĺ
|𝑂𝑃| = 1I£𝑙IJ!𝐶:𝑥2 + 𝑦2 = 4ĐÂ"()¬Y Z
A1
B 3
C2
D2 3
Ġt 2-3Y2024·ĻıļĽ·MĞZī!𝐶:(𝑥−1)2 + (𝑦+ 2)2 = 16I.𝐷(0,1)"ď𝑙 !𝐶ò𝑀,𝑁
9.|𝑀𝑁| = 2 15iI𝑙"GH¬Y Z
A4𝑥+ 3𝑦−3 = 0
B3𝑥−4𝑦+ 4 = 0
C𝑥= 0p4𝑥+ 3𝑦−3 = 0
D4𝑥+ 3𝑦−3 = 0p3𝑥−4𝑦+ 4 = 0.
3 +*,+)*
ę 3Y2024·ľĿŀě·ÃĞZ´µŁ. O É!𝐶:𝑥2 + 𝑦2−4𝑥−4𝑦+ 4 = 0"9Ò+ OAIOBI+.A
¶¬ AIBI£|𝐴𝐵| = Y Z
A 2
B2
C2 2
D4
Ġt 3-1Y2024·TU·ĞģĤĥZī.𝑃!𝐶: (𝑥−𝑎)2 + 𝑦2 = 𝑎2(𝑎> 0)-I.𝐴(0,2)I¡|𝑃𝐴|"6
©7¬1I£. A Ú ! C +"GH¬Y Z
A𝑥= 0p7𝑥+ 24𝑦−48 = 0
B𝑥= 0p7𝑥−24𝑦−48 = 0
C𝑥= 1p24𝑥−7𝑦−48 = 0
D𝑥= 1p24𝑥+ 7𝑦−48 = 0
Ġt 3-2Y2024·ĭĮĢł·ĞģĤĥZī!𝑂:𝑥2 + 𝑦2 = 1I3𝑥+ 4𝑦−10 = 0-"ď.𝑃É!𝑂"
MÒ+I+.¬𝐴I£|𝑃𝐴|"6©7¬Y Z
A1
B 2
C 3
D2
Ġt 3-3Y2024·TU·ĞģĤĥZ𝑦= 𝑥-M. M É! C
(𝑥−2)2 + 𝑦2 = 1"9Ò+I+.A¶
¬ PIQ¡ PQ .(1,3)I£ PQ "GH¬Y Z
A5𝑥−𝑦−2 = 0
B𝑥−5𝑦+ 14 = 0
C5𝑥+ 𝑦−8 = 0
D𝑥+ 5𝑦−16 = 0
4 !-"./012
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ę 4Y2024·Ńń·ĞģĤĥZ«!𝐶:(𝑥−2)2 + (𝑦−1)2 = 36JxW°Ņņ"𝑙: 4𝑥+ 3𝑦−𝑎= 0I¡
!𝐶-Ň{°./𝑙"01¬3I£Q
𝑎= Y Z
A2
B4
C26
D41
Ġt 4-1Y2024·Óňå·°ĞZī!𝐶
𝑥2 + 𝑦2 = 1I𝑙
𝑥−𝑦+ 𝑐= 0I£“𝑐=
2
2 ”\“!𝐶-Ňö
°2./𝑙"01lò
1
2”"Y Z
AĦAxħ;Òñ
Bħ;xĦAÒñ
CĦ;Òñ
DĨxĦA|xħ;
Ġt 4-2Y2024·TU·ĞģĤĥZī𝑙:𝑦= 𝑘𝑥+
2I!𝑥2 + 𝑦2 = 4-Ň{ 3 2./"01å
lò 1I£𝑘= Y Z
A1 p 2
Bʼn1 p−2
C 2pʼn1
D1 pʼn1
Ġt 4-3Y2024·ĚĢ·ÃĞZī𝑂\´µŁ.I¡!𝐶:𝑥2 + 𝑦2 +2𝑥−4𝑦+ 𝑎= 0-{Ú{ 2 2./
2𝑥−𝑦−1 = 0"01¬ 2I£Q
𝑎"ü7ýþ¬Y Z
A(−4−4 5,4 5−4)
B[−4−4 5,4 5−4]
C(−2−2 5,2 5−2)
D[−2−2 5,2 5−2]
5 34*
ę 5Y2024·Ļĭ·ĞģĤĥZī AIB \𝑙
𝑥+
3𝑦−2 = 0-"9.IÚ|𝐴𝐵| = 1IP ¬!𝐷
𝑥2 +
𝑦2 +2𝑥−1 = 0-ŊM.I£ △𝑃𝐴𝐵34"6y7¬Y Z
A
3
2 +
2
B
3
4 +
2
2
C
3
2−2
D
3
4−2
2
Ġt 5-1Y2024·TU·ĞģĤĥZī𝐴(−3,0)I𝐵(0,3)I«𝐶\!𝑀:𝑥2 + 𝑦2−2𝑥−3 = 0-Mď.I£ △𝐴𝐵𝐶
34"6y7 6©7ŋŌlòY Z
A12
B6 2
C6
D3 2
Ġt 5-2Y2024·ĚĢōŎ·MĞZī!𝑄:(𝑥−4)2 + (𝑦−2)2 = 4I.𝑃¬𝑥+ 𝑦+ 2 = 0-"ď.In
𝑃𝑄¬¨"! !𝑄ò𝐴,𝐵9.I£Óŏs𝑃𝐴𝑄𝐵34"6©7¬Y Z
A2 7
B4 7
C2
D4
Ġt 5-3Y23-24 °-·ŐěőŒ·œŔZ𝑃\3𝑥−4𝑦+ 5 = 0-"Mď.I𝑃É!𝐶:𝑥2 + 𝑦2
−4𝑥+ 2𝑦+ 4 = 0"9Ò+I+.A¶¬𝐴,𝐵I£Óŏs𝑃𝐴𝐶𝐵34"6©7¬Y Z
A 2
B2 2
C4 2
D8 2
6 !#$%5"67*
ę 6Y2024·ÓňŕŖŗ·°ĞZ¥𝑦= 𝑥-"M.𝑃ú!(𝑥−4)2 + 𝑦2 = 4Ř+I+.¬𝑄I£|𝑃𝑄|
"6©7¬Y Z
A 2
B2
C 6
D2 2
Ġt 6-1Y2024·ġĢř5·ÃĞZī ⊙𝑀:𝑥2 + 𝑦2−2𝑥−2𝑦−2 = 0I𝑙:2𝑥+ 𝑦+ 2 = 0,𝑃¬ l -"M
ď.IAIB ¬ ⊙𝑀-ŊóxŃg"9.I£cos∠𝐴𝑃𝐵"6©7¬Y Z
A−2 5
5
B−
4
5
C−5
5
D−
3
5
Ġt 6-2Y2024·ĭĮŚśŜ·MĞZđ3à´µ%5I ŝ 𝑑¬. 𝑃cos𝜃,sin𝜃 /
𝑘𝑥−𝑦−3𝑘+ 4 = 0 "01I £ª 𝜃,𝑘ĠiI 𝑑"6y7 6©7ŋŌ¬Y Z
A2
B3
C4
D6
Ġt 6-3Y2024·ġĢĢĩ·MĞZī!𝑂"GH¬
𝑥2 + 𝑦2 = 1I.𝐴(2,0)I𝐵(0,2)I𝑃\Ş𝐴𝐵-"
ď.I𝑃É!𝑂"+I+.A¶¬𝐶I𝐷I{nÓş
①Óŏs𝑃𝐶𝑂𝐷"34"6©7¬ 1z②
Óŏs𝑃𝐶𝑂𝐷"34"6y7¬ 3z③𝑃𝐶⋅𝑃𝐷"6©7¬−1z④𝑃𝐶⋅𝑃𝐷"6y7¬
3
2Î5®{Šîş
"š ¬Y Z
A①③④
B①②④
C②③④
D①④
7 !5"8.87*
ę 7Y2024 °·TU·ŢţZī!𝐴
(𝑥+ 2)2 + 𝑦2 = 25I𝐴¬!¦Iď𝑙.𝑃(2,0)IÚ
!𝐴ò𝐵I𝐶9.Iŝ(𝐵𝐶"5.𝑄"Ťť¬
𝐸.
(1)<
𝐸"GHz
(2)𝐴É9ÒôõA¶¬𝑘1I𝑘2"I
𝐸ò𝑀I𝑁9.IÚ𝑘1𝑘2 = −3I<Ŧ
𝑀𝑁8.
Ġt 7-1Y23-24 Ã-·ŐěŐĴ·œŔZī!¦𝐶𝑦= −2𝑥-IŧÚĒ.𝐴(2,−1)I
𝑥+ 𝑦−1 = 0+"!.
(1)<!𝐶"µŨGHz
(2)Ýò!𝐶-"ŊóM.𝑃I\ũö8.𝐵YxòŁ.𝑂ZĺÂ
|𝑃𝐵|
|𝑃𝑂|Ū¬Æ
ū¡öI<~.𝐵"´µz
¡xöIŬşŭ¥.
Ġt 7-2Y23-24 °-·ŮůŰűŲų·œŔZ!𝐺Ē.(2,2 3),(−4,0)I!¦𝑦= 𝑥-
(1)<!𝐺"µŨGHz
(2)¡!𝐺 𝑥A¶ò𝑀,𝑁9.I𝐴¬𝑙:𝑥= 16-"ď.I𝐴𝑀,𝐴𝑁
!𝐺"ŴM2.A¶¬
𝐸,𝐹I<Ŧ𝐸𝐹Ē8.Iŧ<~8."´µ
Ġt 7-3Y23-24 Ã-·ŵŰŶĴ·œ5Zī!𝐶.𝐴(2,6)I!¦𝑦= 𝑥+ 1-IĐ𝑦()¬2
5
(1)<!𝐶"GHz
(2)¡!𝐶§¨©ò10I.𝐷Ĭ!-ĊďI.𝐵(3,2)Iŝ𝑀¬𝐵,𝐷9."("5.I<𝑀"ŤťGHz
(3)Y2Z"ÒñI¡𝐵𝐷 𝑙:𝑦= 𝑥−2ò.𝑁IŦŭ
|𝐵𝑀| ⋅|𝐵𝑁|Ū¬87
8 ! !"#$%
ę 8Y2024·ŷŸ)Ź·ĞģĤĥZī!𝐸:(𝑥−2)2 + (𝑦−4)2 = 25I!𝐹:(𝑥−2)2 + (𝑦−2)2 = 1I£ĉ9
!"#$%¬Y Z
A^Í
B+
C
DÌ1
Ġt 8-1Y2024·ŮůŰźŻĚ·ĞģĤĥZ!𝐶1:(𝑥−2)2 + (𝑦+ 1)2 = 3 !𝐶2:𝑥2 + (𝑦−1)2 = 3"#$
%\Y Z
A
BÌ+
C^+
D1
Ġt 8-2Y2024·ŐěŐĴ·ÃĞZ¡𝑎𝑥+ 𝑏𝑦= 1 !𝑂:𝑥2 + 𝑦2 = 1+I£!(𝑥−𝑎)2 + (𝑦−𝑏)2 =
1
4
!𝑂Y Z
AÌ+
B
C^+
Dż{:.
Ġt 8-3Y2024·Ěě·ĞģĤĥZī!𝑀:𝑥2 + 𝑦2 +2𝑎𝑦= 0(𝑎> 0)"!¦/3𝑥+ 2𝑦= 2"01\
13I£!𝑀 !𝑁:(𝑥−2)2 + (𝑦+ 2)2 = 1"#$%\Y Z
A1
B
C^+
D^Í
9 9!":(*
ę 9Y2024·ŮůŰ·ĞģĤĥZ!𝐶1:𝑥2 + 𝑦2−2𝑥= 10 !𝐶2:(𝑥+ 2)2 + (𝑦−4)2 = 16":()¬
Y Z
A2 7
B 7
C 6
D2 6
Ġt 9-1Y2024·ŰĢŽŹ·ĞģĤĥZ!𝐶1:𝑥2 + 𝑦2 +2𝑥−8𝑦−8 = 0 !𝐶2:𝑥2 + 𝑦2 +4𝑥−4𝑦−4 = 0"
:()¬Y Z
A 55
5
B2 55
5
C3 55
5
D4 55
5
Ġt 9-2Y2024·İĭžſƀ·ÃĞZī!𝑂1:𝑥2 + 𝑦2 = 5 !𝑂2:𝑥2 + 𝑦2−2𝑥−4𝑦= 0ò AIB 9.I
£|𝐴𝐵| = Y Z
A 5
2
B 5
C 15
D 15
2
Ġt 9-3Y2024·İı·ÃĞZ¡!𝐶1:𝑥2 + 𝑦2 = 1 !𝐶2:(𝑥−𝑎)2 + (𝑦−𝑏)2 = 1":( AB ")¬ 1I£
AB "GH¬Y Z
A2𝑎𝑥+ 𝑏𝑦−1 = 0
B2𝑎𝑥+ 𝑏𝑦−3 = 0
C2𝑎𝑥+ 2𝑏𝑦−1 = 0
D2𝑎𝑥+ 2𝑏𝑦−3 = 0
10 9!"+*
ę 10Y2024·İĭžſƀ·°ĞZī!𝐶1:𝑥2 + 𝑦2 = 1J!𝐶2:𝑥2 + 𝑦2−6𝑥−8𝑦+ 9 = 0I£9!+"
Ò
¬Y Z
A1
B2
C3
D4
Ġt 10-1Y23-24 °·Ěě·ƁƂZ!𝐶1:𝑥2 + 𝑦2 +8𝑥−2𝑦+ 9 = 0J!𝐶2:𝑥2 + 𝑦2 +6𝑥−4𝑦+ 11 = 0
"+GH\Y Z
A𝑦= −𝑥+ 1
B𝑦= −𝑥+ 1p𝑦= 𝑥+ 5
C𝑦= −𝑥+ 5
D𝑦= 𝑥+ 1p𝑦= 2𝑥+ 5
Ġt 10-2Y23-24 °-·Ěěƃƀ·œŔZī!𝐶1:(𝑥+ 1)2 + (𝑦+ 1)2 = 1I!𝐶2:𝑥2 + 𝑦2
−4𝑥−4𝑦−1 = 0I£9!"+Ò
¬Y Z
A1
B2
C3
D4
Ġt 10-3Y23-24 °-·Ńń·ƄŞŢţZī!𝐶1:𝑥2 + 𝑦2 +4𝑥+ 3 = 0I!𝐶2:𝑥2 + 𝑦2−8𝑥+ 12 = 0I
Ā5xC !𝐶1I𝐶2i+"\Y Z
A 3𝑥+ 3𝑦= 0
B 3𝑥−3𝑦= 0
C𝑥+
35𝑦+ 8 = 0
D𝑥−35𝑦−8 = 0
M,P
1Y2024·ĭĮƅƆ·°ĞZī𝑙:𝑘𝑥−𝑦+ 1−𝑘= 0J! ⊙𝑂:𝑥2 + 𝑦2 = 𝑟2(𝑟> 0)I£“𝑟=
2”\“öƇ
M k ĺ l ⊙𝑂+”"Y Z
AĦAíxħ;Òñ
Bħ;íxĦAÒñ
CĦAħ;Òñ
DĨxĦA|xħ;Òñ
2Y2024·ƈƉƈĴ·ĞģĤĥZī!𝑥2 + 𝑦2 +4𝑚𝑥−2𝑚𝑦+ 𝑚= 0(𝑚∈𝑅) 𝑥+I£𝑚= Y Z
A1
B0 p
1
4
C0 p 1
D
1
4
3Y2024·ŮůŰűŲų·ĞģĤĥZī!𝐶1:𝑥2 + 𝑦2 = 4I!𝐶2:𝑥2 + 𝑦2−4𝑥−4𝑦+ 4 = 0I9!":(
®GH\Y Z
A𝑥+ 𝑦+ 2 = 0
B𝑥+ 𝑦−2 = 0
C𝑥+ 𝑦+ 1 = 0
D𝑥+ 𝑦−1 = 0
4Y2024·ƊƅĢĿ·ÃĞZī!𝐶:(𝑥−3)2 + (𝑦−4)2 = 9I𝑙:(𝑚+ 3)𝑥−(𝑚+ 2)𝑦+ 𝑚= 0.£𝑙IJ!
𝐶ĐÂ"()"6©7¬Y Z
A2 7
B 10
C2 2
D 6
5Y2024·^ƋƌƍƎ·°ĞZī! 𝐶₁:(𝑥+ 1)2 + (𝑦+ 1)2 = 2,!𝐶2:𝑥2 + 𝑦2−4𝑥−4𝑦= 0,£9!"+
Ò
¬Y Z
A4
B3
C2
D1
6Y2024·TU·ĞģĤĥZī P ¬𝑙:𝑥−𝑦+ 1 = 0-M.I. P É!𝐶:(𝑥−1)2 + 𝑦2 = 1"MÒ+I
+.¬ AI£|𝑃𝐴|"6©7¬Y Z
A1
B 2
C 3
D2
7Y2024·ŐĢƏĴ·MĞZī. P ¬𝑙1:𝑚𝑥−2𝑦−𝑚+ 6 = 0 𝑙2:2𝑥+ 𝑚𝑦−𝑚−6 = 0(𝑚∈𝑅)"
.I. Q ¬!𝐶:(𝑥+ 3)2 + (𝑦+ 3)2 = 8-"ď.I£|𝑃𝑄|"ü7ýþ¬Y Z
A[2 2,8 2]
B(2 2,8 2]
C[ 2,6 2]
D( 2,6 2]
8Y2024·ŐĢıĿ·°ĞZī!𝐶:(𝑥−4)2 + 𝑦2 = 4I.𝑀Ş𝑦= 𝑥Y0 ≤𝑥≤3Z-I.𝑀É!𝐶"9
Ò+I+.A¶¬𝐴I𝐵In𝐴𝐵¬¨É!𝐶′I£!𝐶′"34"6y7¬Y Z.
Aπ
B2π
C
5π
2
D3π
Ã,m
9Y2024·ŐĢ·ĞģĤĥZī𝑙:𝑦= 𝑘(𝑥−3) +3
𝐶:𝑥2 + 𝑦2−2|𝑥|−2𝑦= 0{:.I£Ɛ
k "
ü7Ån¬Y Z
A0
B1
C2
D3
10Y2024·ĚěƑĩ·ĞģĤĥZī𝑙:𝑘𝑥−𝑦−2𝑘+ 3 = 0I!𝐶:𝑥2−2𝑥+ 𝑦2−8𝑦+ 13 = 0I£Āş
Šî"\Y Z
A!¦𝐶"´µ¬(1,4)
B𝑙 !𝐶ƒƓ{92.
Cª𝑘= 2iI𝑙 !𝐶ò𝑀,𝑁9.I£ △𝐶𝑀𝑁"34¬3 11
10
D.𝐶/𝑙"016yiI𝑘= 1
11Y2024·ĚěƊƔ·°ĞZīď.𝑀,𝑁 A¶!𝐶1:(𝑥−1)2 + (𝑦−2)2 = 1 J 𝐶2:(𝑥−3)2 + (𝑦−4)2 = 3
-Iď.𝑃 𝑥 -I£Y Z
A!𝐶2"§¨¬ 3
B!𝐶1J!𝐶21
C|𝑃𝑀| + |𝑃𝑁|"6©7¬2 10
D.𝑃ƕ!𝐶1"+I£+)6ē¬ 3
°,qr
12Y2024·ġĢ·ĞģĤĥZ!(𝑥−𝑎)2 + (𝑦−2𝑎−3)2 = 9-Ėö92./(2,3)"01¬ 1I£ a "ü7ý
þ\ .
13Y2024·ľĿƖƗ·ĞģĤĥZī!𝐶:𝑥2 + 𝑦2 = 1I𝑙:𝑥+ 𝑦+ 2 = 0I𝑃¬𝑙-"ď.I.𝑃É
!𝐶"9Ò+I+.A¶¬𝐴I𝐵I£𝐴𝐵8. .
14Y2024·ĻĭƘƙ·ĞģĤĥZī!𝐶:𝑥2 + (𝑦−2)2 = 1J!𝐷:𝑥2 + 𝑦2−6𝑥−10𝑦+ 30 = 0IM,N A¶\
! C,D -"ď.IP ¬ x -"ď.I£|𝑃𝑀| + |𝑃𝑁|"6©7\ .
Ó,Kƚ
15Y23-24 Ã-·^ƋƌƍƎ·œŔZī!𝐶"GH
𝑥2 + 𝑦2−2𝑥−4𝑦+ 𝑚= 0
(1)¡𝑦= 𝑥+ 𝑚 ! C ż{:.I< m "ü7ýþz
(2)ª!𝐶IJ𝑙:𝑥+ 2𝑦−4 = 0ĐÂ"()¬2 5iI< m "7
16Y23-24 Ã-·ŐĢƛƜ·œŔZī!𝐶Ē.𝐴(1,1)J𝐵(1,−3)IÚ!¦𝐶𝑥−𝑦−2 = 0-.
(1)<!𝐶GHz
(2)¡!𝐸"GH¬𝑥2 + (𝑦−1)2 = 1I&'!𝐸 !𝐶"#$%.
17Y2024 °·TU·ŢţZī.𝑃(𝑥,𝑦)\!(𝑥+ 2)2 + 𝑦2 = 1-ŊóM.
(1)< P ./3𝑥+ 4𝑦+ 12 = 0"01"6y7J6©7
(2)<𝑥−2𝑦"6y7J6©7
(3)<
𝑦−2
𝑥−1"6y7J6©7
18Y2024 °·TU·ŢţZđ3à´µ%5Iī.𝐴(2,3)I𝐵(5,0)I𝑀\đ3^"Mď.IÚ
ØÙ
|𝑀𝐴|
|𝑀𝐵| = 2Iŝ.𝑀"Ċ¬
𝐸.
(1)<
𝐸"GHz
(2).𝐵"𝑙
𝐸ò𝑃I𝑄9.I¡ △𝑂𝐵𝑃"34\ △𝑂𝐵𝑄"34" 3 ƝI<𝑙"GH
19Y2024·ŮůŰ·ĞģĤĥZī!𝐶:𝑥2−𝑚𝑥+ 𝑦2 +2(2−𝑚)𝑦+ 𝑚−1 = 0,𝑚∈R
(1)Ŧŭ
! C 8.z
(2)ª𝑚= 0iI. P ¬𝑙:
𝑥
6 +
𝑦
3 = 1-"ď.I P É! C "9Ò+I+.A¶¬ AIBI<Óŏs𝑃𝐴𝐶𝐵
346©7Iŧƞ~i AB "GH